On Jan 6, 11:38 pm, John Fields <jfie...@austininstruments.com> wrote:
> On Sat, 5 Jan 2008 19:26:55 -0800 (PST), "Dave.H"
>
>
>
> <the19...@googlemail.com> wrote:
> >On Jan 6, 12:50 pm, John Fields <jfie...@austininstruments.com> wrote:
> >> On Sat, 5 Jan 2008 16:54:53 -0800 (PST), "Dave.H"
> >> >What contact is the internal resistor tied to, the side contact or the=
> >> >bottom contact?
>
> >> ---
> >> What difference does it make?
> >> ---
>
> >> >Also not too sure if 82k is right for 240 volt
> >> >operation.
>
> >> ---
> >> On what do you base your indecision?
>
> >> --
> >> JF
> >The only neons I've ever dealt with before are the common NE-2 which
> >require a 270k resistor for 240 volt operation, I thought all neon
> >indicators did.
>
> ---
> Since the NE-2 and the NE-45 both have maintaining voltages of about
> 55V, then the series resistance can be determined from the source
> voltage and the rated lamp current.
>
> For instance, an NE-2 has a rated current of about 0.5mA, so with a
> 240VRMS source the resistor must drop the difference between the
> source voltage and the lamp's maintaining voltage with the rated
> current going through the lamp:
>
> Vs - Vm 240V - 55V
> R =3D --------- =3D ------------ =3D 3.7E5 ohms =3D 370k ohms.
> Il 5E-4A
>
> Using 270k will result in an RMS current of 685=B5A through the lamp,
> which will cause a brighter glow, but will decrease the life of the
> lamp somewhat.
>
> An NE-45 is rated for 2mA at 120VRMS, so its internal resistor must
> be:
>
> Vs - Vm 120V - 55V
> R =3D --------- =3D ------------ =3D 3.25E4 ohms =3D 32.5k ohms.
> Il 2E-3A
>
> With a 240V source the total resistance needed would be:
>
> 240V - 55V
> R =3D ------------ =3D 9.25E4 ohms =3D 92.5k ohms,
> 2E-3A
>
> so the external resistor would be the difference between the two:
>
> Rext =3D Rt - Rint =3D 92.5k ohms - 32.5k ohms =3D 60k ohms
>
> The closest standard 5% value is 62k which would be fine and would
> extend the life of the lamp.
>
> It (the resistor) would dissipate:
>
> P =3D I=B2R =3D 2E-3A=B2 * 6.2E4R =3D 2.48E-1 watts ~ 0.25 watt,
>
> so you should use a 62kohm +/- 5%, 1/2 watt resistor.
> ---
>
> >Guess you learn something new each day.
>
> ---
>

> ---
>
> >The reason I
> >wanted to know what contact the internal resistor is connected to is
> >so I can put it in series with an external resistor.
>
> ---
> Since the internal resistor is already in series with the lamp,
> connecting an external resistor in series with either the bottom
> contact or the side contact will put it in series with the
> lamp - internal resistor circuit: View in Courier:
>
> . BOTTOM CONTACT
> . /
> .VIN>---[REXT]--->>---[RINT]---+
> . |
> . [LAMP]
> . |
> .VIN>------------>>------------+
> . \
> . SIDE CONTACT
> .
> .
> . BOTTOM CONTACT
> . /
> .VIN>------------>>---[RINT]---+
> . |
> . [LAMP]
> . |
> .VIN>---[REXT]--->>------------+
> . \
> . SIDE CONTACT
>
> .
> . BOTTOM CONTACT
> . /
> .VIN>---[REXT]--->>------------+
> . |
> . [LAMP]
> . |
> .VIN>------------>>---[RINT]---+
> . \
> . SIDE CONTACT
> .
> .
> . BOTTOM CONTACT
> . /
> .VIN>------------>>------------+
> . |
> . [LAMP]
> . |
> .VIN>---[REXT]--->>---[RINT]---+
> . \
> . SIDE CONTACT
>
> --
> JF
Thanks for that information. Got to swap out the old resistors for my
NE-2 lamps with higher rated ones.